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BBA-DBE Bangalore 2025 PYQsLogical Reasoning. Free, no login required.

Logical Reasoning

past year questions, BBA-DBE Bangalore 2025

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past year questions, Logical Reasoning, BBA-DBE Bangalore 2025

Medium

Ravi starts from Point Y and drives 28 km towards West. He then takes a right turn, drives 55 kms, turns left, drives 69 km, turns left and drives 76 km. He then takes a left turn and drives 35 km. He takes a left turn, drives 21 km to stop at Point Z. How far (shortest distance) and towards which direction should he drive in order to reach Point Y again? (All turns are 90 degrees turns only unless specified)

Solution

✅ Correct Option: 3

Let Y be the origin (0,0)(0,0).

  1. Drives 28 km West: Current position (−28,0)(-28, 0).
  2. Right turn, drives 55 km (North): Current position (−28,55)(-28, 55).
  3. Left turn, drives 69 km (West): Current position (−28−69,55)=(−97,55)(-28-69, 55) = (-97, 55).
  4. Left turn, drives 76 km (South): Current position (−97,55−76)=(−97,−21)(-97, 55-76) = (-97, -21).
  5. Left turn, drives 35 km (East): Current position (−97+35,−21)=(−62,−21)(-97+35, -21) = (-62, -21).
  6. Left turn, drives 21 km (North) to stop at Z: Current position (−62,−21+21)=(−62,0)(-62, -21+21) = (-62, 0).

Point Z is at (−62,0)(-62, 0) and Point Y is at (0,0)(0,0). To reach Y from Z, Ravi must drive 62−0=6262-0=62 km in the positive X-direction, which is East.

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