A, B, C, D and E have different ages. Only one person is elder than E. B is younger than C but elder than D. A is elder than C. How many people are elder than C?

From the conditions:

$C > B > D$

$A > C$

So, $A > C > B > D$

A is older than C, B and D, so A is the oldest.

Only one person is older than E, so E is second.

Order from oldest to youngest: $A > E > C > B > D$

People older than C are A and E.

Therefore, $2$ people are older than C.