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How many three digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digit is repeated?

Solution

✅ Correct Option: 3

For divisibility by 5 the units digit must be 5, which can be filled in exactly 1 way. The hundreds place can then take any of the remaining 5 digits and the tens place any of the remaining 4.

Total =5×4×1=20= 5 \times 4 \times 1 = 20.

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