IPMAT Indore 2023 (MCQ) - The set of all real values of x satisfying the inequality x^2(x+1)/(x-1)(2x+1)^3 > 0 is | PYQs + Solutions

IPMAT Indore 2023

Algebra

Easy

$(-\infty, -1)$ U $(-\dfrac{1}{2}, 0)$ U $(1, +\infty)$

$(-1, -\dfrac{1}{2})$ U $(1,+\infty)$

$(-1, 0)$ U $(1,+\infty)$

$(-1, -\dfrac{1}{2})$ U $(0,+\infty)$

✅ Correct Option: 2

Related questions:

IPMAT Indore 2019

The set of values of $x$ which satisfy the inequality $0.7^{(2x^2 - 3x + 4)} < 0.343$ is

IPMAT Indore 2019

If $x ∈ (a, b)$ satisfies the inequality $\dfrac{x - 3}{x^2 + 3x + 2} \geq 1$ , then the largest possible value of $b - a$ is

IPMAT Indore 2020

Consider the following statements:
(i) When (0 < x < 1), then (\frac{1}{1+x} < 1 - x + x^2)
(ii) When (0 < x < 1), then (\frac{1}{1+x} > 1 - x + x^2)
(iii) When (-1 < x < 0), then (\frac{1}{1+x} < 1 - x + x^2)
(iv) When (-1 < x < 0), then (\frac{1}{1+x} > 1 - x + x^2)
Then the correct statements are:

IPMAT Indore 2023 (MCQ) PYQs

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