IPMAT IndoreAlgebra > Medium20212020\frac{2021}{2020}2020202120202019\frac{2020}{2019}20192020120202021\frac{2020}{2021}20212020✅ Correct Option: 1Watch Nowf(x) = nxWatch NowSolved ExampleRelated questions:IPMAT Indore 2022If f(x2+f(y))=xf(x)+yf\left(x^{2}+f(y)\right)=x f(x)+yf(x2+f(y))=xf(x)+y for all non-negative integers xxx and yyy, then the value of [f(0)]2+f(0)[f(0)]^{2}+f(0)[f(0)]2+f(0) equals _________.IPMAT Indore 2022A set of all possible values the function f(x)=x∣x∣f(x)=\dfrac{x}{|x|}f(x)=∣x∣x, where x≠0x \neq 0x=0, takes isIPMAT Indore 2024Let fff and ggg be two functions defined by f(x)=∣x+∣x∣∣f(x) = |x + |x||f(x)=∣x+∣x∣∣ and g(x)=1xg(x) = \frac{1}{x}g(x)=x1 for x≠0x \neq 0x=0. If f(a)+g(f(a))=136f(a) + g(f(a)) = \frac{13}{6}f(a)+g(f(a))=613 for some real aaa, then the maximum possible value off(g(a)) f(g(a))f(g(a)) is: