IPMAT IndoreAlgebra > Medium20212020\frac{2021}{2020}2020202120202019\frac{2020}{2019}20192020120202021\frac{2020}{2021}20212020✅ Correct Option: 1Watch Nowf(x) = nxWatch NowSolved ExampleRelated questions:IPMAT Indore 2022If f(x2+f(y))=xf(x)+yf\left(x^{2}+f(y)\right)=x f(x)+yf(x2+f(y))=xf(x)+y for all non-negative integers xxx and yyy, then the value of [f(0)]2+f(0)[f(0)]^{2}+f(0)[f(0)]2+f(0) equals _________.IPMAT Indore 2019A real-valued function fff satisfies the relation f(x)f(y)=f(2xy+3)+3f(x+y)−3f(y)+6yf(x)f(y) = f(2xy + 3) + 3f(x + y) - 3f(y) + 6yf(x)f(y)=f(2xy+3)+3f(x+y)−3f(y)+6y, for all real numbers xxx and yyy, then the value of f(8)f(8)f(8) isIPMAT Indore 2021If a function f(a)=max(a,0)f(a) = max (a, 0)f(a)=max(a,0) then the smallest integer value of xxx for which the equation f(x−3)+2f(x+1)=8f(x - 3) + 2f(x + 1) = 8f(x−3)+2f(x+1)=8 holds true is _______.