IPMAT Indore 2019 PYQsShort Answers (Quants). Free, no login required.

Algebra

Minima & Maxima

Hard

For all real values of $x$ , $\dfrac{3x^2 - 6x + 12}{x^2 + 2x + 4}$ lies between $1$ and $k$ , and does not take any value above $k$ . Then $k$ equals:

Entered answer:

✅ Correct Answer: 9

IPMAT Indore 2026

If $x$ is a real number such that $\max(\min(x, 2 - x), x - 4, 2x - 8) = \pi - 3$ , then the number of possible values of $x$ is

For all real values of xxx, 3x2−6x+12x2+2x+4\dfrac{3x^2 - 6x + 12}{x^2 + 2x + 4}x2+2x+43x2−6x+12​ lies between 111 and kkk, and does not take any value above kkk. Then kkk equals: