A clock is such that it loses 4 minutes each day. The clock is set right on February 25, 2008 at 2 p.m. How many minutes should be added to get the right time when the clock shows 9 am on 3rd March, 2008?

Actual time passed $=(6$ days $\times$ $24$ hours $)+19$ hours $=163$ hours.

Given that the clock loses $4$ minute in every single day.

$1$ day $=24$ hours $=24 \times 60=1440$ minutes.

In $1440$ minutes, the clock losses $4$ minutes.

Therefore, the minute hand moves at a slightly slower pace.

The speed of minute hand can be expressed as $\frac{1436}{1440}$ fractional part of one minute.

Actual time elapsed is just the reciprocal of it, i.e $=\frac{1440}{1436}$

Thus in the given time of $163$ hours,

Actual time elapsed $=163$ (hours) $\times$ $60$ (minutes) $\times$ $\frac{1440}{1436}$ (minutes hand)

But due to loss in time, the time elapsed by clock is $=163 \times 60$

Difference $=\left(163 \times 60 \times\left(\frac{1440}{1436}\right)\right)-(163 \times 60)$

$=\frac{14083200}{1436}-9780=\frac{9780}{359}$

This difference must be added to get the right time.