IPMAT Indore 2023Geometry > HardEntered answer:✅ Correct Answer: 14Related questions:If θ\thetaθ is the angle between the pair of tangents drawn from the point (0,72)(0,\frac{7}{2})(0,27) to the circle x2+y2−14x+16y+88=0x^2 + y^2 - 14x + 16y + 88 = 0x2+y2−14x+16y+88=0, then tanθ\tan \thetatanθ equalsThe equation x2+y2−2x−4y+5=0x^2 + y^2 - 2x - 4y +5 = 0x2+y2−2x−4y+5=0 representsThe shortest distance from the point (−4,3)(-4,3)(−4,3) to the circle (x2+y2=1)(x^2 + y^2 = 1)(x2+y2=1) is __________.