IPMAT Indore 2023Number System > EasyEntered answer:✅ Correct Answer: 5Related questions:The remainder when 1!+2!+3!+...+95!1! + 2! + 3! + ... + 95!1!+2!+3!+...+95! is divided by 151515 isThe remainder when (2929)29(29^{29})^{29}(2929)29 is divided by 999 isIf the polynomial ax2+bx+5ax^2 + bx + 5ax2+bx+5 leaves a remainder 333 when divided by x−1x - 1x−1, and a remainder 222 when divided by x+1x + 1x+1, then 2b−4a2b - 4a2b−4a equals