IPMAT Indore 2020 (SA) - Ashok purchased pens and pencils in the ratio 2:3 during his first visit and paid Rs. 86 to the shopkeeper. During his second visit, he purchased pens and pencils in the ratio 4:1 and paid Rs. 112. The cost of a pen as well as a pencil in rupees is a positive integer. If Ashok purchased four pens during his second visit, then the amount he paid in rupees for the pens during the second visit is __________. | PYQs + Solutions | AfterBoards
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IPMAT Indore 2020 (SA) PYQs

IPMAT Indore 2020

Arithmetic
>
Ratio, Proportion & Variation

Easy

Ashok purchased pens and pencils in the ratio 2:32:3 during his first visit and paid Rs. 86 to the shopkeeper. During his second visit, he purchased pens and pencils in the ratio 4:14:1 and paid Rs. 112. The cost of a pen as well as a pencil in rupees is a positive integer. If Ashok purchased four pens during his second visit, then the amount he paid in rupees for the pens during the second visit is __________.

Entered answer:

Correct Answer: 100

\newline Alternate Method
Let's denote the cost of one pen as x₹ x and one pencil as y₹ y.
In the first visit, Ashok bought pens and pencils in ratio 2:32: 3.
If he bought 2k2 k pens and 3k3 k pencils, then:
Total cost =2kx+3ky=86=2 k x+3 k y=86
In the second visit, Ashok bought pens and pencils in ratio 4:14: 1.
We're told he bought 44 pens, so he must have bought 11 pencil.
Total cost =4x+y=112=4 x+y=112
From the equations: \newline 2kx+3ky=864x+y=112 (2) \begin{aligned} & 2 k x+3 k y=86 \ldots \\ & 4 x+y=112 \ldots \text { (2) } \end{aligned}
From equation (2): y=1124xy=112-4 x
Substituting into equation (1): \newline 2kx+3k(1124x)=862kx+336k12kx=8610kx+336k=86x=336k8610k\begin{aligned} & 2 k x+3 k(112-4 x)=86 \\ & 2 k x+336 k-12 k x=86 \\ & -10 k x+336 k=86 \\ & x=\frac{336 k-86}{10 k} \end{aligned}
For xx to be a positive integer, (336k86)(336 k-86) must be divisible by 10k10 k.
Trying k=1:x=3368610=25010=25k=1: x=\frac{336-86}{10}=\frac{250}{10}=25
This gives y=1124(25)=112100=12y=112-4(25)=112-100=12
Verifying our answer:
First visit: 2(1)(25)+3(1)(12)=50+36=862(1)(25)+3(1)(12)=50+36=86 \checkmark
Second visit: 4(25)+1(12)=100+12=1124(25)+1(12)=100+12=112 \checkmark
Therefore, during the second visit, Ashok paid 4×25=1004 \times ₹ 25=₹ 100 for the pens.

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