9:{"metadata":[["$","title","0",{"children":"CUET General Test 2024 Slot 1 - A train running at the speed of 80 km/h crosses a 350 m long tunnel in 36 seconds. The length of the train (in m) is: | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined Let the <=ngth of the train be L meters. The total distance covered by the train whi<= crossing the tunnel is the <=ngth of the train plus the <=ngth of the tunnel, which is L + 350 meters. The speed of the train is 80 km/h, which can be converted to meters per second: 80 km/h = 80 1000/3600 = 80000/3600 22.22 m/s . The time taken to cross the tunnel is 36 seconds. Therefore, the distance covered in that time is: Distance = Speed Time = 22.22 36 800 m . Setting up the equation: L + 350 = 800 . Solving for L : L = 800 - 350 = 450 . Thus, the <=ngth of the train is 450 m."}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"CUETGET,GET,Arithmetic,Time, Speed & Distance"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"CUET General Test 2024 Slot 1 - A train running at the speed of 80 km/h crosses a 350 m long tunnel in 36 seconds. The length of the train (in m) is: | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined Let the <=ngth of the train be L meters. The total distance covered by the train whi<= crossing the tunnel is the <=ngth of the train plus the <=ngth of the tunnel, which is L + 350 meters. The speed of the train is 80 km/h, which can be converted to meters per second: 80 km/h = 80 1000/3600 = 80000/3600 22.22 m/s . The time taken to cross the tunnel is 36 seconds. Therefore, the distance covered in that time is: Distance = Speed Time = 22.22 36 800 m . Setting up the equation: L + 350 = 800 . Solving for L : L = 800 - 350 = 450 . Thus, the <=ngth of the train is 450 m."}],["$","meta","9",{"property":"og:url","content":"/past-year-questions/cuet-general-test/2024/slot-1/GET/13"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | CUET General Test 2024 Slot 1 Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"CUET General Test 2024 Slot 1 - A train running at the speed of 80 km/h crosses a 350 m long tunnel in 36 seconds. The length of the train (in m) is: | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined Let the <=ngth of the train be L meters. The total distance covered by the train whi<= crossing the tunnel is the <=ngth of the train plus the <=ngth of the tunnel, which is L + 350 meters. The speed of the train is 80 km/h, which can be converted to meters per second: 80 km/h = 80 1000/3600 = 80000/3600 22.22 m/s . The time taken to cross the tunnel is 36 seconds. Therefore, the distance covered in that time is: Distance = Speed Time = 22.22 36 800 m . Setting up the equation: L + 350 = 800 . Solving for L : L = 800 - 350 = 450 . Thus, the <=ngth of the train is 450 m."}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21"],"error":null,"digest":"$undefined"}

CUET General Test 2024 Slot 1 (GET) PYQs

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