jipmat0024 - An equilateral triangle A B C is inscribed in a circle of radius 20 sqrt(3) ~cm. The centroid of the triangle A B C is at a distance d from the vertex A. then d is equal to ? | PYQs + Solutions

JIPMAT

Geometry

Medium

$15 \mathrm{~cm}$

$20 \mathrm{~cm}$

$20 \sqrt{3} \mathrm{~cm}$

$30 \sqrt{3} \mathrm{~cm}$

✅ Correct Option: 3

Related questions:

The points $(2,2),(6,3)$ and $(4,11)$ are vertices of :

The sides of four triangles are given below. Which of them forms a right triangle ?

(A) $20 \mathrm{~cm}, 22 \mathrm{~cm}, 24 \mathrm{~cm}$

(B) $15 \mathrm{~cm}, 32 \mathrm{~cm}, 37 \mathrm{~cm}$

(D) $6 \mathrm{~cm}, 8 \mathrm{~cm}, 10 \mathrm{~cm}$

Given below are two statements:

Statement I: In $\triangle A B C, A B=6 \sqrt{3} \mathrm{~cm}, A C=12 \mathrm{~cm}$ and $B C=6 \mathrm{~cm}$ , then angle $B=90^{\circ}$

Statement II: In $\triangle A B C$ , is an isosceles with $A C=B C$ . If $A B^{2}=2 AC^{2}$ , Then angle $C=90^{\circ}$

In the light of the above statement, choose the correct answer form the question below.

JIPMAT 2024 (QA) PYQs