9:{"metadata":[["$","title","0",{"children":"JIPMAT 2024 (LR) - Find the missing term that can replace the question mark (?) in the series given below : A2Y, B8V, D33R, ?, K765G. | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined Let's look at the first <=tters of all the given terms first. From A to B, we skip no <=tters. From B to D, we skip one <=tter. Hence, from D, we'll skip 2 <=tters (E,F) to go to G. Hence, Options 2 and 3 are eliminated. Now Options 1 and 4, both have G and M as their first and last <=tters respectively. We only have to figure out the relation between the numbers. Now this one is surely tricky. Taking 2 from the first term, we multiply by 2 and add 4 to go to 8. =22+4=8 Then, from 8, we multiply by 3 and add 9 to go to 33. =83+9=33 The pattern here is multiplying by consecutive numbers, starting from 2, and adding to it, the square of that number. As we can see above, 4=2^2 and 9=3^2 Hence, the next number should be 334+16=132+16=148 (16=4^2) Hence, the answer is G148M."}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"JIPMAT,LR,Logical Reasoning,Coding & Decoding"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"JIPMAT 2024 (LR) - Find the missing term that can replace the question mark (?) in the series given below : A2Y, B8V, D33R, ?, K765G. | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined Let's look at the first <=tters of all the given terms first. From A to B, we skip no <=tters. From B to D, we skip one <=tter. Hence, from D, we'll skip 2 <=tters (E,F) to go to G. Hence, Options 2 and 3 are eliminated. Now Options 1 and 4, both have G and M as their first and last <=tters respectively. We only have to figure out the relation between the numbers. Now this one is surely tricky. Taking 2 from the first term, we multiply by 2 and add 4 to go to 8. =22+4=8 Then, from 8, we multiply by 3 and add 9 to go to 33. =83+9=33 The pattern here is multiplying by consecutive numbers, starting from 2, and adding to it, the square of that number. As we can see above, 4=2^2 and 9=3^2 Hence, the next number should be 334+16=132+16=148 (16=4^2) Hence, the answer is G148M."}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/ipmat-jipmat-past-year-questions/jipmat-2024/LR/16"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IPMAT Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20IPMAT%20JIPMAT%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"JIPMAT 2024 (LR) - Find the missing term that can replace the question mark (?) in the series given below : A2Y, B8V, D33R, ?, K765G. | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined Let's look at the first <=tters of all the given terms first. From A to B, we skip no <=tters. From B to D, we skip one <=tter. Hence, from D, we'll skip 2 <=tters (E,F) to go to G. Hence, Options 2 and 3 are eliminated. Now Options 1 and 4, both have G and M as their first and last <=tters respectively. We only have to figure out the relation between the numbers. Now this one is surely tricky. Taking 2 from the first term, we multiply by 2 and add 4 to go to 8. =22+4=8 Then, from 8, we multiply by 3 and add 9 to go to 33. =83+9=33 The pattern here is multiplying by consecutive numbers, starting from 2, and adding to it, the square of that number. As we can see above, 4=2^2 and 9=3^2 Hence, the next number should be 334+16=132+16=148 (16=4^2) Hence, the answer is G148M."}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21"],"error":null,"digest":"$undefined"}

JIPMAT 2024 (LR) PYQs

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