JIPMAT 2022 (QA) - Match List I with List II. Choose the correct answer from the options given below: | PYQs + Solutions

JIPMAT 2022

Arithmetic

Averages

Medium

\begin{array}{|c|c|c|} \hline \textbf{List I} & \textbf{List II} \\ \hline \text{A. Mean of first five prime numbers is} & \text{I. 12} \\ \hline \text{B. Mean of all factors of 24 is} & \text{II. 7.5} \\ \hline \text{C. Mean of first six multiples of 4 is} & \text{III. 5.6} \\ \hline \text{D. If the mean of } x - 5y, x - 3y, x - y, \\x + y, x + 3y \text{ and } x + 5y \text{ is 12, then } x \text{ is} & \text{IV. 14} \\ \hline \end{array}

Match List I with List II. Choose the correct answer from the options given below:

A-II, B-I, C-III, D-IV

A-III, B-II, C-IV, D-I

A-I, B-IV, C-II, D-III

A-IV, B-III, C-I, D-II

✅ Correct Option: 2

Let's solve each case:

A) First five prime numbers: 2, 3, 5, 7, 11

Mean =

\frac{2+3+5+7+11}{5} = \frac{28}{5} = 5.6

(matches III)

B) Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

\newline

Mean =

\frac{1+2+3+4+6+8+12+24}{8} = \frac{60}{8} = 7.5

(matches II)

C) First six multiples of 4: 4, 8, 12, 16, 20, 24

\newline

Mean =

\frac{4+8+12+16+20+24}{6} = \frac{84}{6} = 14

(matches IV)

D) Mean = 12 for expressions:

\newline

x-5y, x-3y, x-y, x+y, x+3y, x+5y

\newline

Sum =

6x

(y terms cancel)

\newline

\frac{6x}{6} = 12

\newline

Therefore

x = 12

(matches I)

Hence, Option 2 is the answer.