Skip to main contentSkip to question navigationSkip to solution

CUET General Test 2024 PYQs

CUET General Test 2024

Geometry
>
Triangles

Medium

In triangle ABCABC, points DD and EE are on ABAB and ACAC respectively such that DEDE is parallel to BCBC. If AD=6AD = 6 cm, DB=4DB = 4 cm, AE=9AE = 9 cm, then the length of ECEC (in cm) is:

Correct Option: 3
Since DE is parallel to BC, by the Basic Proportionality Theorem (or Thales' theorem), we have:
ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC}
Substituting the known values:
64=9EC\frac{6}{4} = \frac{9}{EC}
Cross-multiplying gives:
6EC=496 \cdot EC = 4 \cdot 9
6EC=366 \cdot EC = 36
Dividing both sides by 6:
EC=6EC = 6 cm.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question