IPMAT Rohtak 2020 (QA) PYQs

The greatest number among $2^{300}$, $3^{200}$, $4^{100}$, $2^{100} + 3^{100}$ is

If $2^{x} = 3^{y} = 6^{-z}$, then $(\frac{1}{x} + \frac{1}{y} + \frac{1}{z})$ is equal to

Simplify : $\dfrac{\sqrt[4]{0.0625}+\sqrt[3]{0.008}+\sqrt{0.09}-1}{\sqrt[3]{62 \cdot 5 \times \sqrt[5]{32}}}$