Arithmetic

Averages

Easy

The average age of a group of 9 friends is 22 years. LAVGIR is the youngest and his age is 6 years, then what happened to be the average age of the friends just before LAVGIR was born?

✅ Correct Option: 1

Let $x$ be the sum of ages of 9 friends, then

$\frac{x}{9}=22$

$x=22\times9=198$

One of those $x$ is LAVGIR, who is 6 years old. Age of the group just before LAVGIR $=198-6(9)=198-54=144$

And now that LAVGIR doesn't exist yet, there are 8 friends now, hence average age $=\frac{144}{8}=18$

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The average age of a group of 9 friends is 22 years. LAVGIR is the youngest and his age is 6 years, then what happened to be the average age of the friends just before LAVGIR was born?

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