9:{"metadata":[["$","title","0",{"children":"IPMAT Indore 2025 - Area of a regular octagon inscribed in a circle of radius 1 unit is: | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined

This is a regular octagon (all sides of the octagon are same) inscribed in a circ<=. We can solve this easily by eliminating options: Area of circ<= (r = 1 unit) is 3.14 units square. Option 1 = 2 1.4 = 2.8 Option 2 = 2 + 1.4 = 3.4 Option 3 = 9/2.8 = ~3.2 Option 4 = sqrt(10) = 3.16 -> (Use the calculator if needed) Only one option is <=ss than the circ<= itself (because the octagon is inscribed within it). Hence, option 1 becomes the answer."}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"IPMAT Indore,MCQ,Geometry,Polygons"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"IPMAT Indore 2025 - Area of a regular octagon inscribed in a circle of radius 1 unit is: | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined

This is a regular octagon (all sides of the octagon are same) inscribed in a circ<=. We can solve this easily by eliminating options: Area of circ<= (r = 1 unit) is 3.14 units square. Option 1 = 2 1.4 = 2.8 Option 2 = 2 + 1.4 = 3.4 Option 3 = 9/2.8 = ~3.2 Option 4 = sqrt(10) = 3.16 -> (Use the calculator if needed) Only one option is <=ss than the circ<= itself (because the octagon is inscribed within it). Hence, option 1 becomes the answer."}],["$","meta","9",{"property":"og:url","content":"/ipmat-indore-past-year-questions/2025/MCQ/16"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IPMAT Indore 2025 Preparation"}],["$","meta","11",{"property":"og:image","content":"https://balti.afterboards.in/G0nDiwygM1LrpZQ"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"IPMAT Indore 2025 - Area of a regular octagon inscribed in a circle of radius 1 unit is: | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined

This is a regular octagon (all sides of the octagon are same) inscribed in a circ<=. We can solve this easily by eliminating options: Area of circ<= (r = 1 unit) is 3.14 units square. Option 1 = 2 1.4 = 2.8 Option 2 = 2 + 1.4 = 3.4 Option 3 = 9/2.8 = ~3.2 Option 4 = sqrt(10) = 3.16 -> (Use the calculator if needed) Only one option is <=ss than the circ<= itself (because the octagon is inscribed within it). Hence, option 1 becomes the answer."}],["$","meta","17",{"name":"twitter:image","content":"https://balti.afterboards.in/G0nDiwygM1LrpZQ"}],["$","link","18",{"rel":"shortcut icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","19",{"rel":"icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","20",{"rel":"icon","href":"https://www.afterboards.in/icons/windows11/Square44x44Logo.altform-lightunplated_targetsize-256.png","sizes":"256x256","type":"image/png"}],["$","link","21",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-512-512.png","sizes":"512x512","type":"image/png"}],"$L18","$L19","$L1a","$L1b","$L1c"],"error":null,"digest":"$undefined"}

IPMAT Indore 2025 (MCQ) PYQs

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