IPMAT IndoreGeometry > Medium26252116✅ Correct Option: 2Related questions:IPMAT Indore 2019Points PPP, QQQ, RRR, and SSS are taken on sides ABABAB, BCBCBC, CDCDCD, and DADADA of square ABCDABCDABCD respectively, so that APPB=BQQC=CRRD=DSSA=1n\frac{AP}{PB} = \frac{BQ}{QC} = \frac{CR}{RD} = \frac{DS}{SA} = \frac{1}{n}PBAP=QCBQ=RDCR=SADS=n1. Then the ratio of the area of PQRSPQRSPQRS to the area of ABCDABCDABCD is