IPMAT Indore 2020 - The average marks of 6 students in a test is 64. All the students got different marks, one of the students obtained 70 marks and all other students scored 40 or above. The maximum possible difference between the second highest and the second lowest marks is | PYQs + Solutions

IPMAT Indore

Arithmetic

Hard

✅ Correct Option: 2

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IPMAT Indore 2021

A class consists of 30 students. Each of them has registered for 5 courses. Each course instructor conducts an exam out of 200 marks. The average percentage marks of all 30 students across all courses they have registered for, is 80%. Two of them apply for revaluation in a course. If none of their marks reduce, and the average of all 30 students across all courses becomes 80.02%, the maximum possible increase in marks for either of the 2 students is

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Suppose $a, b$ and $c$ are three real numbers such that Max $(a, b, c) \ +$ Min $(a, b, c) = 15$ , and Median $(a, b, c) \ -$ Mean $(a, b, c) = 2.$ Then the median of $a, b$ and $c$ is

IPMAT Indore 2024

The following table shows the number of employees and their median age in eight companies located in a district.

Company	Number of employees	Median age
A	32	24
B	28	30
C	43	39
D	39	45
E	35	49
F	29	54
G	23	59
H	16	63

It is known that the age of all employees are integers. It is known that the age of every employee in A is strictly less than the age of every employee in B, the age of every employee in B is strictly less than the age of every employee in C, ..., the age of every employee in G is strictly less than the age of every employee in H.

The highest possible age of an employee of company A is:

IPMAT Indore 2020 (MCQ) PYQs

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