9:{"metadata":[["$","title","0",{"children":"iimkbmsat0025 - Find the area of a trapezium whose parallel sides measure 25 cm and 13 cm, while the other two sides measure 15cm each. | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined Given: - Paral<=l sides: 25 cm and 13 cm - Non-paral<=l sides: 15 cm each Since both non-paral<=l sides are equal (15 cm each), this is an isosce<=s trapezium.

When we drop perpendiculars from the shorter paral<=l side to the lon>=r one, we create two identical right triang<=s on the sides. The base of each triang<= = 25 - 132 = 122 = 6 cm Using Pythagoras theorem: height^2 + 6^2 = 15^2 height^2 + 36 = 225 height^2 = 189 height = sqrt(189) = sqrt(9 21) = 3sqrt(21) cm

Area of trapezium = 12 (sum of paral<=l sides) height Area = 12 (25 + 13) 3sqrt(21) Area = 12 38 3sqrt(21) Area = 19 3sqrt(21) Area = 57sqrt(21) cm²"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"IIM-K (BMSAT),QA,Geometry,Quadrilaterals"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"iimkbmsat0025 - Find the area of a trapezium whose parallel sides measure 25 cm and 13 cm, while the other two sides measure 15cm each. | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined Given: - Paral<=l sides: 25 cm and 13 cm - Non-paral<=l sides: 15 cm each Since both non-paral<=l sides are equal (15 cm each), this is an isosce<=s trapezium.

Area of trapezium = 12 (sum of paral<=l sides) height Area = 12 (25 + 13) 3sqrt(21) Area = 12 38 3sqrt(21) Area = 19 3sqrt(21) Area = 57sqrt(21) cm²"}],["$","meta","9",{"property":"og:url","content":"/iimk-bmsat-past-year-questions/2025/QA/32"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | JIPMAT Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"iimkbmsat0025 - Find the area of a trapezium whose parallel sides measure 25 cm and 13 cm, while the other two sides measure 15cm each. | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined Given: - Paral<=l sides: 25 cm and 13 cm - Non-paral<=l sides: 15 cm each Since both non-paral<=l sides are equal (15 cm each), this is an isosce<=s trapezium.

Area of trapezium = 12 (sum of paral<=l sides) height Area = 12 (25 + 13) 3sqrt(21) Area = 12 38 3sqrt(21) Area = 19 3sqrt(21) Area = 57sqrt(21) cm²"}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21"],"error":null,"digest":"$undefined"}

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