Q1:2019Geometry > MediumQ1:2019Geometry>MediumAnswer options1443−48πcm2144\sqrt{3} - 48\pi cm^21443−48πcm21213−36πcm2121\sqrt{3} - 36\pi cm^21213−36πcm21443−36πcm2144\sqrt{3} - 36\pi cm^21443−36πcm21213−48πcm2121\sqrt{3} - 48\pi cm^21213−48πcm2Correct AnswerOption 1Correct AnswerExplanation →